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4.2 Nitration

4.2 Nitration

  • The mechanism is similar to the one used for bromination.
  • There is a mechanism for the aromatic substitution reaction when benzene is treated with a complex.
    • The same mechanism is used to install a br on the ring.
    • Don't look back at that mechanism to copy it.
    • When you are done, compare your answer to the answer in the back of the book to make sure that all of your arrows were drawn correctly.
  • When treated with a suitable source of I+, aromatic rings will also undergo iodination.
    • If you are responsible for knowing how to iodinate benzene, you should look in your textbook and lecture notes.
    • The mechanism is the same as what we have seen.
    • The mechanism of how I+ is formed will be the only difference.
  • There is a mechanism for the reaction between benzene and I+.
  • The mechanism of an aromatic substitution reaction was shown in the previous section.
    • The mechanism is the same if you are installing I+ on the ring.
    • This same mechanism explains how an aromatic ring can be used to install an E+).
  • We need NO+ to form nitrobenzene.
  • This complex could be a source of NO+.
  • We need to take a close look at how NO+ is formed.
  • You can't do that because it would give five bonds to the central nitrogen atom.
    • Nitrogen can't have five bonds because it only has four orbitals.
    • Charge separation is needed to draw nitric acid.
  • It's true that nitric acid and sulfuric acid are acidic.
  • It might make us uncomfortable to use nitric acid as a base, but that is exactly what is happening.
  • The acid removes a protons from the acid.
  • This probably would make more sense.
    • It is likely to happen a lot more often.
    • The un charged oxygen atom is more difficult to remove than the negative charged oxygen atom.
    • The transfers of protons are not always permanent.
  • All of the time, particles are being transferred back and forth.
    • The only thing that can happen when the oxygen atom is negatively charged is for the protons to be given back to nitric acid.
  • The un charged oxygen atom can remove the protons.
  • NO+ is generated when this happens.
  • The same mechanism that we saw in the previous section is used once again: NO+ on and then H+ off.
  • There is plenty of water because nitric and sulfuric acids are both aqueous solutions.
    • The mechanism is very similar to what we have seen before.
  • We have seen how to install a halogen on an aromatic ring and a nitro group.
    • Make sure you are familiar with the reagents needed to perform these reactions before we move on.
    • In order to achieve the desired transformation, identify the reagents that you would use.
  • A piece of paper is needed to record your answer.
  • We will learn how to install an alkyl group.
  • A methyl group is the simplest of the alkyl groups.
  • The logic we have developed in this chapter would allow us to use CH+.
  • It would not be very stable.
    • We don't use primary or methyl when drawing mechanisms.
    • We are trying to make a carbocation.
    • The answer is yes.
    • We will use the same method that we used in the previous sections.
  • We are not forming a free carbocation that can float off into solution.
  • We must see this as a complex that can serve as a source of CH+.
  • We have seen the same mechanism over and over again.
  • A Friedel-Crafts alkylation is a process in which an alkyl group is put on an aromatic ring.
    • It works well for installing groups on the ring.
  • There is a simple reason for this.
    • Since we are forming a complex with a carbocationic character, it is1-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-6556 It is not possible to rearrange a carbocation.
    • An ethyl carbocation cannot be rearranged to become more stable.
  • A mixture of products is what we observe.
    • If you use a Friedel-Crafts alkylation to look for carbocations, you need to be careful.
  • We already know that we will get some rearrangement, and we will not get a good yield of the desired product.
  • We will likely get a mixture of products if we just use 1-chlorohexane.
  • We need a trick.
    • There is a trick.
    • We need to look at a similar reaction that bears the name Friedel-Crafts to see how it works.
    • Let's compare an acyl group with an alkyl group.
  • The first reagent is called an acyl chloride, and we are already familiar with its role.
  • There is a positive charge.
  • There are no side products that would result from a carbocation.
  • Let's point out a very important feature when we take a close look at the acylation above.
  • We will only focus on one method right now, but we will see two other methods in the future, one using basic conditions and the other using neutral conditions.
  • In the presence of zinc that has been treated so that its surface is an alloy of zinc and mercury, the C--O bond is completely reduced and replaced with two C--H bonds.
  • A Friedel-Crafts acylation can be followed up by a Clemmensen reduction, as a clever way of installing an alkyl group on an aromatic ring.
    • When you want to install an acyl group on the ring, you won't want to do a Clemmensen reduction afterwards.
  • You would just use Friedel-Crafts acylation to achieve this transformation.
    • There is no need for a reduction in the bond because we don't want to reduce it.
  • An alkyl group needs to be installed on a benzene ring.
    • We want to see if we can do this in one step.
    • We have to worry about a carbocation because we can't do it in one step.
  • What reagents would you use to accomplish the transformation?
    • Friedel-Crafts acylation is used in some situations, while Friedel-Crafts alkylation is used in other situations.
  • All of the possible rearrangements can be considered.

4.2 Nitration

  • The mechanism is similar to the one used for bromination.
  • There is a mechanism for the aromatic substitution reaction when benzene is treated with a complex.
    • The same mechanism is used to install a br on the ring.
    • Don't look back at that mechanism to copy it.
    • When you are done, compare your answer to the answer in the back of the book to make sure that all of your arrows were drawn correctly.
  • When treated with a suitable source of I+, aromatic rings will also undergo iodination.
    • If you are responsible for knowing how to iodinate benzene, you should look in your textbook and lecture notes.
    • The mechanism is the same as what we have seen.
    • The mechanism of how I+ is formed will be the only difference.
  • There is a mechanism for the reaction between benzene and I+.
  • The mechanism of an aromatic substitution reaction was shown in the previous section.
    • The mechanism is the same if you are installing I+ on the ring.
    • This same mechanism explains how an aromatic ring can be used to install an E+).
  • We need NO+ to form nitrobenzene.
  • This complex could be a source of NO+.
  • We need to take a close look at how NO+ is formed.
  • You can't do that because it would give five bonds to the central nitrogen atom.
    • Nitrogen can't have five bonds because it only has four orbitals.
    • Charge separation is needed to draw nitric acid.
  • It's true that nitric acid and sulfuric acid are acidic.
  • It might make us uncomfortable to use nitric acid as a base, but that is exactly what is happening.
  • The acid removes a protons from the acid.
  • This probably would make more sense.
    • It is likely to happen a lot more often.
    • The un charged oxygen atom is more difficult to remove than the negative charged oxygen atom.
    • The transfers of protons are not always permanent.
  • All of the time, particles are being transferred back and forth.
    • The only thing that can happen when the oxygen atom is negatively charged is for the protons to be given back to nitric acid.
  • The un charged oxygen atom can remove the protons.
  • NO+ is generated when this happens.
  • The same mechanism that we saw in the previous section is used once again: NO+ on and then H+ off.
  • There is plenty of water because nitric and sulfuric acids are both aqueous solutions.
    • The mechanism is very similar to what we have seen before.
  • We have seen how to install a halogen on an aromatic ring and a nitro group.
    • Make sure you are familiar with the reagents needed to perform these reactions before we move on.
    • In order to achieve the desired transformation, identify the reagents that you would use.
  • A piece of paper is needed to record your answer.
  • We will learn how to install an alkyl group.
  • A methyl group is the simplest of the alkyl groups.
  • The logic we have developed in this chapter would allow us to use CH+.
  • It would not be very stable.
    • We don't use primary or methyl when drawing mechanisms.
    • We are trying to make a carbocation.
    • The answer is yes.
    • We will use the same method that we used in the previous sections.
  • We are not forming a free carbocation that can float off into solution.
  • We must see this as a complex that can serve as a source of CH+.
  • We have seen the same mechanism over and over again.
  • A Friedel-Crafts alkylation is a process in which an alkyl group is put on an aromatic ring.
    • It works well for installing groups on the ring.
  • There is a simple reason for this.
    • Since we are forming a complex with a carbocationic character, it is1-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-65561-6556 It is not possible to rearrange a carbocation.
    • An ethyl carbocation cannot be rearranged to become more stable.
  • A mixture of products is what we observe.
    • If you use a Friedel-Crafts alkylation to look for carbocations, you need to be careful.
  • We already know that we will get some rearrangement, and we will not get a good yield of the desired product.
  • We will likely get a mixture of products if we just use 1-chlorohexane.
  • We need a trick.
    • There is a trick.
    • We need to look at a similar reaction that bears the name Friedel-Crafts to see how it works.
    • Let's compare an acyl group with an alkyl group.
  • The first reagent is called an acyl chloride, and we are already familiar with its role.
  • There is a positive charge.
  • There are no side products that would result from a carbocation.
  • Let's point out a very important feature when we take a close look at the acylation above.
  • We will only focus on one method right now, but we will see two other methods in the future, one using basic conditions and the other using neutral conditions.
  • In the presence of zinc that has been treated so that its surface is an alloy of zinc and mercury, the C--O bond is completely reduced and replaced with two C--H bonds.
  • A Friedel-Crafts acylation can be followed up by a Clemmensen reduction, as a clever way of installing an alkyl group on an aromatic ring.
    • When you want to install an acyl group on the ring, you won't want to do a Clemmensen reduction afterwards.
  • You would just use Friedel-Crafts acylation to achieve this transformation.
    • There is no need for a reduction in the bond because we don't want to reduce it.
  • An alkyl group needs to be installed on a benzene ring.
    • We want to see if we can do this in one step.
    • We have to worry about a carbocation because we can't do it in one step.
  • What reagents would you use to accomplish the transformation?
    • Friedel-Crafts acylation is used in some situations, while Friedel-Crafts alkylation is used in other situations.
  • All of the possible rearrangements can be considered.